Grover is a town in Taylor County, Wisconsin, in the United States. As of the 2000 census, the town population was 233.
According to the United States Census Bureau, the town has a total area of 184.8 square km (71.4 square miles). 183.0 square km (70.7 square miles) of it is land and 1.8 square km (0.7 square miles) of it (0.99%) is water.
As of the census of 2000, there were 233 people, 93 households, and 70 families residing in the town. The population density was 1.3/square km (3.3/square mi). There were 135 housing units at an average density of 0.7/square km (1.9/ square mi). The racial makeup of the town was 97.42% White and 2.58% Native American, Hispanic or Latino of any race were 0.43% of the population.
There were 93 households out of which 28.0% had children under the age of 18 living with them, 72.0% were married couples living together, 1.1% had a female householder with no husband present, and 23.7% were non-families. 21.5% of all households were made up of individuals and 10.8% had someone living alone who was 65 years of age or older. The average household size was 2.51 and the average family size was 2.89.
In the town the population was spread out with 22.7% under the age of 18, 6.9% from 18 to 24, 30.5% from 25 to 44, 24.0% from 45 to 64, and 15.9% who were 65 years of age or older. The median age was 40 years. For every 100 females, there were 102.6 males. For every 100 females age 18 and over, there were 102.2 males.
The median income for a household in the town was $38,125, and the median income for a family was $42,500. Males had a median income of $29,531 versus $25,875 for females. The per capita income for the town was $18,031. About 2.9% of families and 2.5% of the population were below the poverty line, including none of those under the age of eighteen and 11.1% of those sixty five or over.